8=-4.9t^2+30t

Solution for 8=-4.9t^2+30t equation:

8=-4.9t^2+30t

We move all terms to the left:

8-(-4.9t^2+30t)=0

We get rid of parentheses

4.9t^2-30t+8=0

a = 4.9; b = -30; c = +8;
Δ = b2-4ac
Δ = -302-4·4.9·8
Δ = 743.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-\sqrt{743.2}}{2*4.9}=\frac{30-\sqrt{743.2}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+\sqrt{743.2}}{2*4.9}=\frac{30+\sqrt{743.2}}{9.8}
$